Recursive Odd Number Function
Boolean isOdd(int num) { if (num == 2147483647) { return true; } else if (num == 0) { return false; } return isOdd(num+2) }
A pixelated code screenshot shows a recursive Boolean function checking whether a number is odd. The joke is that it only handles the maximum 32-bit integer and zero as base cases, so other inputs recurse indefinitely or overflow instead of returning a result. It is shared as a programmer reaction to flawed recursion and edge-case bugs.
code text / текст кодаfunction declaration / объявление функцииconditional statement / условный операторrecursive call / рекурсивный вызовBoolean return value / логическое возвращаемое значениеnumber 2147483647 / число 2147483647number 0 / число 0dark background / тёмный фонpixelated font / пиксельный шрифт
- @ithueti / 1467 2019-10-18
- @right_wing_dev_squads / 3601 2022-03-07
- @right_wing_dev_squads / 5057 2022-10-07
- Type
- image
- Size
- 680×406 · 26.9 KiB
- Mood
- саркастичный
- Language
- en
- Added